MySQL中查询某一天, 某一月, 某一年的数据代码详解

吾爱主题 阅读:171 2024-04-05 14:21:04 评论:0

今天

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1 select * from 表名 where to_days(时间字段名) = to_days(now());

昨天(包括昨天和今天的数据)

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1 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

昨天(只包括昨天)

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1 SELECT * FROM 表名 WHERE DATEDIFF(字段,NOW())=-1; -- 同理,查询前天的就是-2

近7天

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1 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY ) <= date (时间字段名)

近30天

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1 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY ) <= date (时间字段名)

本月

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1 SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

上一月

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1 SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

查询本季度数据

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1 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());

查询上季度数据

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1 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

查询本年数据

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1 select * from `ht_invoice_information` where YEAR (create_date)= YEAR (NOW());

查询上年数据

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1 select * from `ht_invoice_information` where year (create_date)= year (date_sub(now(),interval 1 year ));

查询当前这周的数据

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1 SELECT name ,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime, '%Y-%m-%d' )) = YEARWEEK(now());

查询上周的数据

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1 SELECT name ,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime, '%Y-%m-%d' )) = YEARWEEK(now())-1;

查询上个月的数据

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1 2 3 4 5 6 select name ,submittime from enterprise where date_format(submittime, '%Y-%m' )=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH ), '%Y-%m' ) select * from user where DATE_FORMAT(pudate, '%Y%m' ) = DATE_FORMAT(CURDATE(), '%Y%m' ) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate, '%y-%m-%d' )) = WEEKOFYEAR(now()) select * from user where MONTH (FROM_UNIXTIME(pudate, '%y-%m-%d' )) = MONTH (now()) select * from user where YEAR (FROM_UNIXTIME(pudate, '%y-%m-%d' )) = YEAR (now()) and MONTH (FROM_UNIXTIME(pudate, '%y-%m-%d' )) = MONTH (now()) select * from user where pudate between 上月最后一天 and 下月第一天

查询当前月份的数据

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1 select name ,submittime from enterprise where date_format(submittime, '%Y-%m' )=date_format(now(), '%Y-%m' )

查询距离当前现在6个月的数据

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1 select name ,submittime from enterprise where submittime between date_sub(now(),interval 6 month ) and now();

总结

以上所述是小编给大家介绍的MySQL中查询某一天, 某一月, 某一年的数据代码详解,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对服务器之家网站的支持!
如果你觉得本文对你有帮助,欢迎转载,烦请注明出处,谢谢!

原文链接:https://www.cnblogs.com/zhangweibin/archive/2019/06/11/11002142.html

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