SQL 列不同的表查询结果合并操作
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2024-04-01 23:50:34
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比如table1的列为 id, user_id, type_id,pro_id;
table2的列为 id,user_id,collect_id;分别如下图所示
table1:
table2:
将两个表的查询结果合并到一起的查询语句为
?1 2 3 | select *, null as collect_id from table1 where user_id = 527 union select id,user_id, null as type_id, null as pro_id, collect_id from table2 where user_id = 527; |
结果为:
其实就是把对应的列补充到没有该列的表中,在例子中就是把collect_id补充到table1中,
把type_id,pro_id补充到table2中。
补充知识:sql结果集合并用union all 不同表的列合并用join
结果集合并用union all 不同表的列合并用join
?1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 | SELECT "模块名" , "事件编码" , "点击数量" , "使用时长(单位:分)" FROM ( SELECT T.fun_name as "模块名" , T.event_code as "事件编码" , SUM (click_records) as "点击数量" FROM ( SELECT m.* FROM default .daily_new_clientrpt_master m WHERE event_id in ( SELECT max (event_id) AS "事件" from default .daily_new_clientrpt_master group by user_name,fun_code ORDER BY "事件" DESC ) ) T where day = today() GROUP BY "模块名" , "事件编码" ) T5 JOIN ( SELECT T.fun_name as "模块名" , T.event_code as "事件编码" , round( sum (stay_time)/60000,0) as "使用时长(单位:分)" FROM ( SELECT m.* FROM default .daily_new_clientrpt_master m WHERE event_id in ( SELECT "事件" FROM ( SELECT max (event_id) AS "事件" , max (stay_time) AS "事件1" from default .daily_new_clientrpt_master group by user_name,fun_code ORDER BY "事件1" DESC ) ) ) T where day = today() AND like (event_code, '%10000' ) GROUP BY "模块名" , "事件编码" ) T6 ON T5. "模块名" =T6. "模块名" AND T5. "事件编码" =T6. "事件编码" |
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原文链接:https://blog.csdn.net/u010498402/article/details/78038553
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