mysql中TIMESTAMPDIFF案例详解

1.  Syntax

TIMESTAMPDIFF(unit,begin,end); 根据单位返回时间差,对于传入的begin和end不需要相同的数据结构,可以存在一个为Date一个DateTime

2. Unit

支持的单位有

• MICROSECOND
• SECOND
• MINUTE
• HOUR
• DAY
• WEEK
• MONTH
• QUARTER
• YEAR

3. Example

下面这个例子是对于TIMESTAMPDIFF最基本的用法，

• 3.1 求 2017-01-01 - 2017-02-01 之间有几个月

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SELECT TIMESTAMPDIFF( MONTH , '2017-01-01' , '2017-02-01' ) as  result;   + --------+ | result | + --------+ | 1 | + --------+ 1 row in set (0.00 sec)

• 3.2 求 2017-01-01 - 2017-02-01 之间有几天

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SELECT TIMESTAMPDIFF( DAY , '2017-01-01' , '2017-02-01' ) as  result;   + --------+ | result | + --------+ | 31 | + --------+ 1 row in set (0.00 sec)

•  3.3 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:00 之间有几分钟

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SELECT TIMESTAMPDIFF( MINUTE , '2017-01-01 08:00:00' , '2017-01-01 08:55:00' ) result;   + --------+ | result | + --------+ | 55 | + --------+ 1 row in set (0.00 sec)

•  3.4 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:33 之间有几分钟

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SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;   +--------+ | result | +--------+ | 55 | +--------+ 1 row in set (0.00 sec)

•  3.5 对于DAY， MINUTE进行计算DIFF时，会直接将相对应的DAY，MINUTE相减

• 3.6 对于 SECOND 会怎样计算呢

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SELECT TIMESTAMPDIFF( SECOND , '2017-01-01 08:00:00' , '2017-01-01 08:55:33' ) result;   55 * 60 + 33 = 3333 + --------+ | result | + --------+ |   3333 | + --------+ 1 row in set (0.00 sec)

• 3.7 如何求数据库中两个date字段的diff
  • 3.7.1  建表 ?

    1 2	CREATE TABLE demo (id INT AUTO_INCREMENT PRIMARY KEY , start_time DATE NOT NULL , end_time DATE NOT NULL ); Query OK, 0 rows affected (0.10 sec)

  • 3.7.2  添加数据 ?

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    INSERT INTO demo(start_time, end_time) VALUES ( '1983-01-01' , '1990-01-01' ), ( '1983-01-01' , '1989-06-06' ), ( '1983-01-01' , '1985-03-02' ), ( '1983-01-01' , '1992-05-05' ), ( '1983-01-01 11:12:11' , '1995-12-01' );

  • 3.7.3 直接query数据 ?

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    select * from demo; + ----+------------+------------+ | id | start_time | end_time | + ----+------------+------------+ | 1 | 1983-01-01 | 1990-01-01 | | 2 | 1983-01-01 | 1989-06-06 | | 3 | 1983-01-01 | 1985-03-02 | | 4 | 1983-01-01 | 1992-05-05 | | 5 | 1983-01-01 | 1995-12-01 | + ----+------------+------------+ 5 rows in set (0.00 sec)

  • 3.7.4 计算duration ?

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    select *, TIMESTAMPDIFF( YEAR , start_time, end_time) as duration from demo;   + ----+------------+------------+----------+ | id | start_time | end_time | duration | + ----+------------+------------+----------+ | 1 | 1983-01-01 | 1990-01-01 | 7 | | 2 | 1983-01-01 | 1989-06-06 | 6 | | 3 | 1983-01-01 | 1985-03-02 | 2 | | 4 | 1983-01-01 | 1992-05-05 | 9 | | 5 | 1983-01-01 | 1995-12-01 | 12 | + ----+------------+------------+----------+ 5 rows in set (0.00 sec)

  • 3.7.5 其他应用 ?

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    select *, if(TIMESTAMPDIFF( YEAR , end_time, CURRENT_TIMESTAMP ())< 26 , '< 26' , '>= 26' ) as result from demo;   + ----+------------+------------+--------+ | id | start_time | end_time | result | + ----+------------+------------+--------+ | 1 | 1983-01-01 | 1990-01-01 | >= 26 | | 2 | 1983-01-01 | 1989-06-06 | >= 26 | | 3 | 1983-01-01 | 1985-03-02 | >= 26 | | 4 | 1983-01-01 | 1992-05-05 | < 26 | | 5 | 1983-01-01 | 1995-12-01 | < 26 | + ----+------------+------------+--------+ 5 rows in set (0.00 sec)

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原文链接：https://blog.csdn.net/baiyaoliang7445/article/details/102218767